a scooter acquires a velocity of 36 km/h in 10 seconds just after the start. Calculate the acceleration of the scooter.
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Answered by
790
Solution :
Given :
u (initial velocity) = 0 (rest) , v (final velocity) = 36 km/ hr = 36 × (1000/3600)
v = 36× 5/18 = 10 m/s. , t = 10s
From first equation of motion , v = u + at
10 = 0 + a ×10
10 = 10a
a = 10/10
a = 1 m/s²
acceleration of the scooter = 1 m/s²
Hence, the acceleration of the scooter is 1 m/s².
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NeymarDaSilva:
r u sure this is correct...
Answered by
317
According to the question, Initial velocity of the scooter = 0 ( starts from rest ) Final velocity of the scooter = 36 km/h = 36 X 5/ 18 = 10 m/s Time taken to reach the final velocity = 10 seconds Acceleration = v - u / t a = 10 - 0 / 10 a = 10 / 10 a = 1 m/s²
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