A scooter acquires a velocity of 36 km/h in 10 seconds just after the start. Calculate the acceleration of the scooter.
Answers
Answered by
12
Given,
final velocity, v=36 km/h
initial velocity, u=0
now acceleration=?
we know,
acceleration=v-u/t
=32-0/10
=3.6 km/h sq....
hope this may help u....n dont forget to mark it as brainliest
final velocity, v=36 km/h
initial velocity, u=0
now acceleration=?
we know,
acceleration=v-u/t
=32-0/10
=3.6 km/h sq....
hope this may help u....n dont forget to mark it as brainliest
Shobana13:
Sorry to say actually ur answer is wrong.. First we have change km/h into m/s.. In the question they mentioned the velocity as 36 km/h.. It wasn't mentioned as 36m/s
Answered by
5
v= 36 km/h= 36×5/18=10m/s
u=0
t=10 secs
a=?
a = v-u/t
a=10-0/10
a= 1m/s sq
a=1×18/5
a=18/5
a= 3.16 km/hr sq
Hope it helps u :)
u=0
t=10 secs
a=?
a = v-u/t
a=10-0/10
a= 1m/s sq
a=1×18/5
a=18/5
a= 3.16 km/hr sq
Hope it helps u :)
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