Question

A scooter acquires a velocity of 36 km/ h in 10 seconds just after the start. Calculate (1) the acceleration of the scooter (2) the distance travelled by the scooter for attaining this velocity.A scooter acquires a velocity of 36 km/ h in 10 seconds just after the start. Calculate (1) the acceleration of the scooter (2) the distance travelled by the scooter for attaining this velocity.A scooter acquires a velocity of 36 km/ h in 10 seconds just after the start. Calculate (1) the acceleration of the scooter (2) the distance travelled by the scooter for attaining this velocity.

Answer 1

Solution :

Given :  

u (initial velocity) = 0 (rest) , v (final velocity) = 36 km/ hr = 36 × (1000/3600)

v = 36× 5/18 = 10 m/s. , t = 10s

From first equation of motion , v = u + at

10 = 0 + a ×10

10 = 10a

a = 10/10

a = 1 m/s²

acceleration of the scooter = 1 m/s²

Hence, the acceleration of the scooter is 1 m/s².

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Answer 2

Answer:

Acceleration = 1 m/s distance travelled = 50 m

Explanation:

ACCELERATION:

u = 0 m/s

v = 36 km/h = 10 m/s                                                (36 x 5/18 = 10)

t = 10 seconds

Acceleration = (v - u)/t

                     = (10 - 0)/10

                     = 1 $m / s^{2}$    

DISTANCE:

$s = ut + (1/ 2)at^{2}$

$s = 0 + (1/2)(1)(10^{2})$

$s = 50 m$