Question

A scooter acquires a velocity of 36 km/h in 10 seconds just after the start. It takes 20

seconds to stop. Find the ratio of acceleration and retardation in these case.FAST PLEASE​

Answer 1

Answer:CASE 1:

Initial velocity, u = 0m/s

Final velocity, v = 36 km/hr = 10 m/s

Time, t = 10 s

Acceleration, a = (v - u) / t

∴a = (10 - 0) / 10

    = 10/10

∴a = 1 m/s²

Thus, acceleration of the scooter is 1 m/s².

CASE 2:-

Initial velocity, u = 36 km/h = 10 m/s

Final velocity, v = 0 m/s

Time, t = 20 s

Acceleration, a = (v - u) / t

∴a = (0 - 10) / 20

    = -10/20

∴a = - 0.5 m/s²

Thus, acceleration of the scooter is -0.5 m/s². The negative sign indicates retardation.

Explanation:

Answer 2

Answer:

∴a = - 0.5 m/s²

Thus, acceleration of the scooter is -0.5 m/s².