Question

A scooter acquires a velocity of 36 km/h in 10 seconds just after the start. It takes 20 seconds to stop. Calculate the acceleration in two cases.

Answer 1

v=36km/h
time=10sec =10sec/120sec =(1/12)h
acceleration =v-u/t
=36km/h-0/1/12
=432km/h square

deacceleration =v-u/t
=0-36km/h/t
= -432km/h square

Answer 2

Answer:

Case 1:

u =0

t =10sec.

v =36km/h =36×5/18 =10m/s

a =v-u/t =10-0/10 =10/10 =1m/s^2

Case 2:

u =36km/h

v =0

t =20sec.

a =v-u/t =0-10/20 = -10/20 = -0.5m/s^2

Explanation:

Hope it helps you