a scooter acquires a velocity of 36 km/h in 10s just after the start. calculate the acceleration of the scooter.
Answers
Answered by
10
as you see we have
u=0. and v=36km/h=10m/s
v=u+at
10=0. +a×10
a=1m^s2
u=0. and v=36km/h=10m/s
v=u+at
10=0. +a×10
a=1m^s2
Anonymous:
bro a= 3.6 km/h^2
Answered by
12
hey dear
here is your answer
given data :
initial velocity (u) = 0
final velocity = (v) = 36 km/hr or 10 m/s
time (t) = 10 seconds
to find : acceleration
so, here we go
solution :
by using first equation of motion
v = u+at
10 = 0+10a
10a = 10
a = 1 m/s²
hope it helps :)
here is your answer
given data :
initial velocity (u) = 0
final velocity = (v) = 36 km/hr or 10 m/s
time (t) = 10 seconds
to find : acceleration
so, here we go
solution :
by using first equation of motion
v = u+at
10 = 0+10a
10a = 10
a = 1 m/s²
hope it helps :)
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