Question

A scooter acquires a velocity of 36 km/hr in 10 seconds just after the start. Calculate the acceleration of the scooter. ​

Answer 1

Answer:

36 = 10m/s

using 1 eq of motion

u+at = v

after start defines u = 0

0 + 10a = 10

a = 1m/s²

Answer 2

v=36 km/hr

v=36×

18

5

=10 m/s

u=0

t=10 sec

v=u+at

10=0+a (10)

10=10a