Question

A scooter acquires a velocity of 36 km per hour in 10 seconds just after the start. Calculate the acceleration.​

Answer 1

Answer:

Given :  

u (initial velocity) = 0 (rest) , v (final velocity) = 36 km/ hr = 36 × (1000/3600)

v = 36× 5/18 = 10 m/s. , t = 10s

From first equation of motion , v = u + at

10 = 0 + a ×10

10 = 10a

a = 10/10

a = 1 m/s²

acceleration of the scooter = 1 m/s²

Hence, the acceleration of the scooter is 1 m/s².

HOPE THIS ANSWER WILL HELP YOU…..

Answer 2

Explanation:

Acceleration (a) = (v - u)/t

During the starting , u = 0

v = 36 km/hr = 36 × 5/18 = 10 m/Second

Now ,

a = (10 - 0)/10 = 10/10 = 1 m/sec²