Question

a scooter acquires a velocity of 36 km per hour in 10 seconds just after the start.calculate the acceleration of the scooter. ​

Answer 1

Given :-

☄ Initial velocity of scooter, u = zero

☄ Final velocity of scooter, v = 36 km/h = 10m/s

☄ Time taken, t = 10 sec

To Find :-

the acceleration of the scooter

Solution :-

as we are providing with the final velocity and time we can using equation of motion

so, using equation of motion .i.e.,

➠ v = u + at

here,

v = final velocity, u = initial Velocity, a = accerlation and t = time

➠ 10 = 0 + (a)(10)

➠ 10 = 10a

➠ a = 10/10

➠ a = 1m/s²

thus, acceleration of scooter is 1m/s²

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Answer 2

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Question:-

A scooter acquires a velocity of 36 km per hour in 10 seconds just after the start.calculate the acceleration of the scooter.

$\text{\large\underline{\green{Given:-}}}$

• Final Velocity = 36 km/h.
• Initial Velocity = 0 m/s.
• Time taken = 10 seconds.

$\text{\large\underline{\orange{To\:Find:-}}}$

• What is the acceleration of the scooter?

Formula to be used:

• v = u + at

$\text{\large\underline{\purple{Solution:-}}}$

as we are providing with the final velocity and time we can using equation of motion

so, using equation of motion .i.e.,

• ➠ v = u + at

Here,

v = final velocity, u = initial Velocity, a = accerlation and t = time

➠ 10 = 0 + (a)(10)

➠ 10 = 10a

➠ a = 10/10

➠ a = 1m/s²

Hence, the acceleration of scooter is 1 m/s².

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