Question

A Scooter acquires a velocity of 36 km per hour in 10 second just after the start calculate the accelation of the scooter

Answer 1

Answer:

1 m / s²

Explanation:

Scooter started from rest

Initial velocity ( u ) = 0 m / s

Final velocity ( v ) = 36 Km / h = 36 × ( 5 / 18 ) = 10 m / s

Time ( t ) = 10 seconds

Let the acceleration be 'a' m / s²

From 1st equation of motion

⇒ v = u + at

⇒ 10 = 0 + 10a

⇒ 10 / 10 = a

⇒ 1 = a

⇒ a = 1

Hence, the acceleration of the scooter is 1 m / s²

Answer 2

$\large{\underline{\underline{\mathfrak{Answer :}}}}$

• Acceleration of scooter is 1m/s²

$\rule{200}{0.5}$

$\underline{\underline{\mathfrak{Step-By-Step-Explanation :}}}$

Given :

• Initial velocity (u) = 0m/s
• Final velocity (v) = 36 km/h = 10 m/s
• Time (t) = 10 s

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To Find :

• Acceleration of scooter

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Solution :

We have formula for acceleration :

$\large{\boxed{\boxed{\sf{a \: = \: \dfrac{v \: - \: u}{t}}}}} \\ \\ \implies {\sf{a \: = \: \dfrac{10 \: - \: 0}{10}}} \\ \\ \implies {\sf{a \: = \: \dfrac{10}{10}}} \\ \\ \implies {\sf{a \: = \: 1}} \\ \\ \underline{\sf{\therefore \: Acceleration \: of \: scooter \: is \: 10 \: ms^{-2}}}$