Question

A scooter acquires a velocity of 36km/h in 10 secs just after the start.calculate the acceleration of the scooter

Answer 1

Explanation:

u=0 km/h

v=36 km/h

t=10 sec=10/3600=0.0027 h

a=(v-u)/t

=(36-0)/0.0027

=13333.33km/h^-2

Answer 2

Answer:

Final velocity (v)-> 36km/h

Initial velocity (u)-> 0

Time = 10 s = 0. 00277778 h

So

Acceleration(A) = (V -U)/T

A = (36-0)/0.00277778

A = 12959. 98 km/h²(-)