A scooter acquires a velocity of 36km /h. in 10second just after the start calculate the acceleration of the scottet
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a=(v-u)/t
a=(36-0)/(10/3600)
a=12960 km/h^2 hope u like it....
a=(36-0)/(10/3600)
a=12960 km/h^2 hope u like it....
Answered by
2
3.6km/sec . a=(v-u)÷t
u=0(initial velocity)
u=0(initial velocity)
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