Question

A scooter acquires a velocity of 36km/hr in 10 sec just after the start it takes 20sec to stop, calculate the acceleration in two cases

Answer 1

u=0m/s

v=36km/h=10m/s

t=10s

a=v-u/t

 =10-0/10

 =1m/s^2

u=10m/s

v=0

t=10s

a=-10/10

  =-1m/s^2

Hope it helps.

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