Question

A scooter acquires a velocity of 36km/hr in 10 seconds just after the start.it takes 20 seconds to stop.calculate the acceleration and distance

Answer 1

From the equation of motion, we get,

v = u + a t

Initial velocity, u=0              [ Since, body starts from rest ]

Final velocity, v=36 km/h = 36 x
$\frac{5}{18}$
                  [1 km/h=
$\frac{5}{18}$
]

Therefore, v = 10 m/s

t = 10 sec

v = u + a t

v - u = a t
$\frac{v - u}{t} = a$
$\frac{10 - 0}{10}$
=a

Therefore, a = 1 m/s2

Hence, the acceleration of the scooter is 1 m/s2.

Answer 2

36km/hr=10m/s
v=u+at
0=10+20a
-10=20a
-0.5m/s=a Ans
s=ut+1/2at^2
s=10×20+1/2×-1/2×20×20
s=200-100
s=100m Ans