Question

A scooter acquires a velocity of 54kmph in 15secs just after the start. It takes 20secs to stop. Calculate acceleration in both the cases

Answer 1

u=0

v=54kmph = 54×5/18=3*5=15m/s

t=15 sec

a=?

a=(v-u)/t

a=15-0/15=1m/s^2 ----------- CASE 1

u=15m/s

v=0

t=20 sec

a=v-u/t

a=0-15/20

a=-3/4

a=-0.75m/s^2