A scooter acquires the velocity of 36km/h in 10s just after the start. Identify the
initial and final velocity and find the acceleration
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Answer:
Explanation:
CASE 1:
Initial velocity, u = 0m/s
Final velocity, v = 36 km/hr = 10 m/s
Time, t = 10 s
Acceleration, a = (v - u) / t
∴a = (10 - 0) / 10
= 10/10
∴a = 1 m/s²
Thus, acceleration of the scooter is 1 m/s².
CASE 2:-
Initial velocity, u = 36 km/h = 10 m/s
Final velocity, v = 0 m/s
Time, t = 20 s
Acceleration, a = (v - u) / t
∴a = (0 - 10) / 20
= -10/20
∴a = - 0.5 m/s²
Thus, acceleration of the scooter is -0.5 m/s². The negative sign indicates retardation.
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