Question

A scooter acquires velocity of 72km/h in 10 seconds after the start and takes 20 seconds to stop . Calculate the acceleration in both cases.

Answer 1

Explanation:

hope it will help thank you

Answer 2

Answer:

1st case=2 m/$s^{2}$

2nd case=1m/$s^{2}$

Explanation:

1st CASE:

U=0

V=72km=72x5/18

=360/18 = 20m/s

10 sec

a= v-u/t =0-20/10

=2m/$s^{2}$

CASE 2:

U=20 m/s

v =0

t=20 sec

a= v-u/t=0-20/20

=-20/20 =-1m/$s^{2}$