Question

A scooter before overhauling requires 2/3 h service time every 45 days, while after overhauling, it requires 2/3 h service time every 60 days. What fraction of pre-overhauling service time is saved in the latter case?​

Answer 1

Time required for service before overhauling = 2/3h = 40 min in 45 days

and time required for service after overhualing =2/3h= 40 min in 60 days

Now,LCM of 45 and 60 = 180 days

time required for service before overhauling is 180 days = 40 x 4 = 160 min

and time required for service before overhauling is 180 days =40 x 3 = 120 min

∴ fraction of time saved = 160 - 120/160 =40/160 = 1/4

Answer 2

Step-by-step explanation:

Match the following A. 1 bookmark. 2 status bar 3 notes pane 4 place holder 5 symbol B a allows to add notes b ₹ c shows active slides number d insert tab e text box frames