Math, asked by yuvrajsathe937, 1 month ago

A scooter costing Rs. 12,000 was sold for
Rs 10,400 after two years, find the
percentage loss.
A
40/3
B
10/3
С
44/3
D
42/3​

Answers

Answered by bhoomikasrilanth123
2

Answer:

Loss % = loss ×100/CP

LOSS = 12000- 10400 = 1600

LOSS% = 1600×100/12000

= 160000/12000

= 133.33

therefore , option A is correct that is 40/3

Answered by qwsuccess
1

Given: Cost Price of the scooter = Rs. 12,000

           Selling price of the scooter = Rs. 10,400

To find: The percentage loss

Solution: According to the given question,

Cost Price (CP) = Rs. 12,000

Selling Price (SP) = Rs. 10,400

Since, Cost Price > Selling Price, seller suffered a loss.

∵ Loss = Cost Price - Selling Price

⇒ Rs. 12,000 - Rs. 10,400 =  Rs. 1,600

∵ Loss percentage = \frac{Loss}{Cost \ Price} \ * \ 100

\frac{1,600}{12,000} \ * \ 100  = \frac{40}{3} %

Hence, the loss percentage is \frac{40}{3} % (Option A).

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