Question

a scooter from rest moves in a straight line with uniform acceleration and covers 64m in 4s. Calculate its acceleration and final velocity

Answer 1

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore Acceleration=8\:m/s^{2}}}$

${\bold{\therefore Final\:velocity=32\:m/s}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a scooter from rest moves in a straight line with uniform acceleration and covers 64m in 4s.

• We have to Calculate its acceleration and final velocity.

$\underline \bold{Given : } \\ \implies Initial \: velocity(u) = 0 \: m/s \\ \\ \implies Distance(s) = 64 \: m \\ \\ \implies Time(t) = 4 \: sec \\ \\ \underline \bold{To \: Find : } \\ \implies Acceleration(a) = ? \\ \\ \implies Final \: velocity(v) = ?$

• According to given question :

$\bold{Using \: third \: equation \: of \: motion : } \\ \implies s = ut + \frac{1}{2} {at}^{2} \\ \\ \implies 64 = 0 \times 4 + \frac{1}{2} \times a \times {4}^{2} \\ \\ \implies 64 = 8a \\ \\ \implies a = \frac{ \cancel{64}}{ \cancel{8}} \\ \\ \bold{\implies a = 8 \: m /{s}^{2} } \\ \\ \bold{Using \: first \: equation \: of \: motion : } \\ \implies v = u + at \\ \\ \implies v = 0 + 8 \times 4 \\ \\ \bold{\implies v = 32 \: m/s}$

Answer 2

$\huge\sf{Answer:-}$

According to the given question:-

• A scooter from rest moves in a straight line with uniform acceleration and covers 64m in 4s.We have to calculate its acceleration and final velocity.

Hence,

0 m/s is the initial velocity ,64 m is the distance and 4 sec is the time.

We have to find the acceleration and final velocity.

= S = ut + 1/2 at²

= 64 = 0 × 4 + 1/2 × a × 4²

= 64 = 8a

= a = 64/8

= a = 8m/s²

From Equation(1)

v - u + at

= v = a + 8 × 4

= V = 32 m/s