Question

A scooter going due east at 10m/s turns right through an angle 90 degdee. If the speed of the scooter remains unchanged in taking turn the change in the velocity of scooter is

Answer 1

heya.....


The answer is 14.14 m/s in s-w direction

V1=10i^
 v2=10j^
resultant=√(10)sq+(10)sq=√200=10√2=10×1.41=14.14 m/s ans

tysm.#gozmit

Answer 2

Answer:

The change in the velocity of scooter is 14.14 m/s.

Explanation:

Given that,

Velocity of scooter = 10 m/s due east

Angle = 90°

If the speed of the scooter remains unchanged in taking turn the change in the velocity of scooter is

The change in velocity is given by

$\Delta v=\sqrt{v_{1}^2+v_{2}^2+2v_{1}v_{2}\cos\theta}$

$\Delta v=\sqrt{10^2+10^2+2\times10\times10\cos90^{\circ}}$

$\Delta v =\sqrt{10^2+10^2+0}$

$\Delta v=10\sqrt{2}$

$\Delta v=14.14\ m/s$

Hence, The change in the velocity of scooter is 14.14 m/s.