a scooter initially at rest picks up a velocity of 20 m/s over a distance of
40 m. calculate acceleration and time in which it attains the velocity of 20 m/s.
Answers
Answered by
16
heyy!! here's ur ans
given = u=0
v=20m/sec
s(distance)=40m
a=?
t=?
2as= v^2-u^2
2a*40=20^2
2a*40=400
2a=400/40
2a=10
a=5
a=v-u/t
5 =20-0/t
5=20/t
t=20*5
t=100sec
hope u r satisfied
given = u=0
v=20m/sec
s(distance)=40m
a=?
t=?
2as= v^2-u^2
2a*40=20^2
2a*40=400
2a=400/40
2a=10
a=5
a=v-u/t
5 =20-0/t
5=20/t
t=20*5
t=100sec
hope u r satisfied
Answered by
2
intial velocity=0m/s
final velocity=20m/s
distance=40m
acceleration=final velocity-initial velocity/distance
=20-0/40=0.2m/s^2(ans)
final velocity=20m/s
distance=40m
acceleration=final velocity-initial velocity/distance
=20-0/40=0.2m/s^2(ans)
dibakardas1970:
thanks
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