Question

A scooter is moving at a speed of 10m/s is stopped by applying breaks which produce a uniform acceleration of -0.5m/s . how much distance will be covered by the scooter before it stops

Answer 1

Answer:

100 meter is the answer.......

Answer 2

Answer:

100 m distance covered.

Explanation:

Given,

Initial velocity = 10 m/s, Final velocity = 0 m/s, Acceleration = -0.5 m/s^2

Distance = ?

v^2 - u^2 = 2as (Third Equation Of Motion)

0^2 - 10^2 = 2(-0.5)(s)

0 - 100 = -1s

-100 = -1s

s = 100 m