Question

a scooter is moving at a speed of 36 km is brought to rest in 10 sec. calculate retardation​

Answer 1

Given :

• Initial velocity (u) = 36 km/h
• Final velocity (v) = 0 m/s (as it brought to rest)
• Time (t) = 10 seconds

To find :

• Retardation

According to the question,

Note : We have ti change 36 km/h into m/s. So,it will be 10 m/s.

By using Newtons first equation of motion,

➞ v = u + at

Where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time

➞ Substituting the values,

➞ 0 = 10 + a × 10

➞ 0 - 10 = 10a

➞ - 10 = 10a

➞ - 10 ÷ 10 = a

➞ - 1 = a

So,the retardation is 1 m/s².

_________________________

More formulas :

Newton's first equation of motion :

• v = u + at

Newton's second equation of motion :

• s = ut + ½ at²

Newton's third equation of motion :

• v² = u² + 2as