Question

A scooter is moving with the speed of 36 km h-¹ when brakes are applied it stops after 10 sec .calculate the acceleration

Answer 1

Answer:

CASE 1:

Initial velocity, u = 0m/s

Final velocity, v = 36 km/hr = 10 m/s

Time, t = 10 s

Acceleration, a = (v - u) / t

∴a = (10 - 0) / 10

     = 10/10

∴a = 1 m/s²

Thus, acceleration of the scooter is 1 m/s².

CASE 2:-

Initial velocity, u = 36 km/h = 10 m/s

Final velocity, v = 0 m/s

Time, t = 20 s

Acceleration, a = (v - u) / t

∴a = (0 - 10) / 20

     = -10/20

∴a = - 0.5 m/s²

Thus, acceleration of the scooter is -0.5 m/s². The negative sign indicates retardation.

Answer 2

Answer:

1 m/s².

Explanation:

Initial velocity, (u) = 0m/s

Final velocity, (v) = 36 km/hr = 10 m/s

Time, t = 10 s

Acceleration, a = (v - u) / t

∴a = (10 - 0) / 10

 = 10/10

∴a = 1 m/s²

so accelaration is 1 m/s².

hpe it helps