Physics, asked by anujsinghtomar1763, 8 months ago

A scooter is traveling at speed of 36 km /hour after 1 second its velocity become 45 km/hour calculate the acceleration experienced by the scooter

Answers

Answered by Rohit18Bhadauria
75

Given:

Initial velocity of scooter,u= 36 km/h

Final velocity of scooter,v= 45 km/h

Time taken by scooter

To Find:

The acceleration experienced by the scooter

Solution:

We know that,

  • According to first equation of motion for constant acceleration,

\purple{\boxed{\bf{v=u+at}}}

where,

v is final velocity

u is initial velocity

a is acceleration

t is time taken

━━━━━━━━━━━━━━━━━━━━

It is given that,

\longrightarrow\sf{u=36\ km/h=36\times\dfrac{5}{18}\ m/s=10\ m/s}

\longrightarrow\sf{v=45\ km/h=45\times\dfrac{5}{18}\ m/s=\dfrac{25}{2} \ m/s}

━━━━━━━━━━━━━━━━━━━━

Let the acceleration of scooter be 'a'

So, on applying first equation of motion on scooter, we get

\longrightarrow\sf{v=u+at}

\longrightarrow\sf{\dfrac{25}{2} =10+a(1)}

\longrightarrow\sf{\dfrac{25}{2}-10=a}

\longrightarrow\sf{\dfrac{25-20}{2}=a}

\longrightarrow\sf{\dfrac{5}{2}=a}

\longrightarrow\sf{a=\dfrac{5}{2}}

\longrightarrow\sf\green{a=2.5\ m/s^{2}}

Hence, the acceleration experienced by the scooter is 2.5 m/s².

Answered by Anonymous
3

✴️ QUESTIONS ✴️

A scooter is traveling at speed of 36 km /hour after 1 second its velocity become 45 km/hour calculate the acceleration experienced by the scooter?

✴️To find ✴️

calculate the acceleration experienced by the scooter

✴️ANSWER ✴️

✍️GIVEN:

intial velocity (u)=36 km/h

final velocity (v)= 45km/h

Time taken( t )=1 s

✴️ FORMULA USED ✴️

______________

______________

v=u+at-------(1)

______________

______________

✴️km/h converted into m/s ✴️

1 km = 1000m

1 h = 3600 s

So 1km /h = 1000/3600 = 5/18 = 0.28 m/sec

If you want to change km/h to m/s simply multiply the given no. by 5/18 .

Now,

u=36km/h

=36×5/18m/s

=10m/s

v=45km/h

=45×5/18m/s

=25/2m/s

=12.5m/s

substituting u and v in eq (1)

a is a acceleration

v=u+at

12.5=10+a(1)

12.5-10/1=a

a=2.5m/s.

ACCELERATION EXPERIENCED BY THE SCOOTER IS 2.5m/s.

Similar questions