Question

A scooter moving at 10 km/h is stopped by applying breaks which produce a uniform acceleration of -0.5 m/s2 .how much distance will be covered by the scooter before it stop

Answer 1

u = 10 m/s (given)

v = 0 ( the scooter stops)

a = -0.5 m/s2

According to 3rd equation of kinematics -

v2 = u2 + 2*a*s.

 02 = 102 + 2*-0.5*s.

 0 = 100 + (-s).

-100= - s (cancel the negative sign from both sides)

s = 100.

Hope you got it!