Question

A scooter moving at a speed 10m per second it is stop by applying brakes which produce uniform acceleration of minus 0.5 m per square how much distance will be covered by the scooter before its stop

Answer 1

u = 10 m/s (given)

v = 0 ( the scooter stops)

a = -0.5 m/s2

According to 3rd equation of kinematics -

v2 = u2 + 2*a*s.

 02 = 102 + 2*-0.5*s.

 0 = 100 + (-s).

-100= - s (cancel the negative sign from both sides)

s = 100.

Hope you got it!

Answer 2

Aɴsᴡᴇʀ:

• The distance covered by the scooter before it stops = 100 metres

Gɪᴠᴇɴ:

• A scooter moving at a speed 10m per second it is stop by applying brakes which produce uniform acceleration of minus 0.5 m per square.

Nᴇᴇᴅ Tᴏ Fɪɴᴅ:

• The distance covered by the scooter before it stops = ?

Solution:

Bʏ ᴛʜᴇ ᴛʜɪʀᴅ ᴇǫᴜᴀᴛɪᴏɴ ᴏғ ᴍᴏᴛɪᴏɴ ᴡᴇ ɢᴇᴛ:

• v² = u² + 2as

Pᴜᴛᴛɪɴɢ Tʜᴇ Vᴀʟᴜᴇs:

➦ 0² = 10² + 2 × -0.5 × s

➦ 0 = 100 + 2 × - 5/10 × s

➦ 0 = 100 - 1s

➦ s = 100 metres

Tʜᴇʀᴇғᴏʀᴇ:

• The distance covered by the scooter before it stops is 100 metres.

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