Question

a scooter moving at a speed of 10 m/s is stopped by applying brakes which produces a uniform acceleration of -0 .5 ms-2 how much distance will covered by the scooter before it stops

Answer 1

Answer:100m

Explanation:HERE,u=10m/s;v=0m/s;a=-0.5m/s²

BY THIRD EQUATION OF MOTION WE KNOW THAT:

2as=v²-u²

BY REARRANGING;

s=v²-u²÷2a

s=(0)²-(10)²÷2×(-0.5)

s=-100÷(-1)

s=100m

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Answer 2

Given,

u=10m/s

v=0m/s

a= -0.5m/s^2

s=?

We know that

v^2=u^2+2as

0^2=10^2+2×(-0.5)×s

0=100-1s

0-100=1s

100=1s

100/1=s

s=100m