Question

a scooter moving at a speed of 10 m/s is stopped by applying breaks which produce a uniform acceleration of -0.5m/s*.how much distance will be covered by the scooter before it stops

Answer 1

initial velocity of scooter=10 m/s
final velocity......................=0 m/s
acceleration of ..............=-0.5 m/s²
apply formula v²-u²=2as
-100=2x-0.5xs
-100=-s
s=100
distance traveled by scooter before it stops is 100m

Answer 2

Answer: Initial velocity of scooter=10m/s

Final velocity=0m/s

Acceleration of scooter = -0.5 m/s^2

Using formula =V2 -U2 =2as

-100=2×0.5×S

-100-S

Ans. S-100

Explanation: