Question

A scooter moving at a speed of 10 m/s is stopped by applying brakes, which produces an acceleration of -.5 m/s2 . How much distance will be covered by the scooter, before it stops?

Answer 1

Given:

• Initial velocity,u = 10 m/s

• Final velocity,v = 0 m/s

• Acceleration, a = -5 m/s²

To be calculated:

Calculate the distance covered by the scooter before it stops.

Formula used:

v² = u² + 2as

Solution:

According to the third equation of motion,

v² = u² + 2as

★ Putting the values in the third equation of motion

we get :

⇒ ( 0 )² = ( 10 )² + 2 × -5 × s

⇒ 0 = 100 + ( - 10s )

⇒ 10s = 100

⇒ s = 100/10

⇒ s = 10 m

Thus, the distance covered by the scooter is 10 metres.

Answer 2

Hey User,

Here is Your answer.

GIVEN

Initial Velocity= 10m/s

Acceleration = -5m/s.

Final Velocity= 0m/s.

To Find-->The distance Coverred by Scooter Before it ends.

First we have to find the time taken by Scooter to stop.

Applying First equation of Motion.

V=U+at.

0=10+-5×t

0=10-5t

-10=-5t

t= 2 second.

Hence,The time taken by Scooter to stop is 2 second.

Now,

Using Second equation of motion to find "DISTANCE".

S=Ut+1/2a(t)^2

S=10(2)+1/2×-5×4

S=20+-10

S=10m.

Hence,

The Distance Covered by Scooter before stopping is 10m.

Thank You!.