a scooter moving at a speed of 10m/s is stopped by applying brakes which produced an uniform acceleration of -0.5m/s2 how much distance will be covered by the scooter before it stops?
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Answered by
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S = (v² - u²) / (2a)
= [0 - (10 m/s)²] / [2 × (-0.5 m/s²)]
= 100 m
Distance covered by scooter before it stops is 100 m
= [0 - (10 m/s)²] / [2 × (-0.5 m/s²)]
= 100 m
Distance covered by scooter before it stops is 100 m
Answered by
5
given
u 10 m/s
and
v is 0 as scooter stops
using v^2=u^2-2as
we can find the answer
distance is 100
u 10 m/s
and
v is 0 as scooter stops
using v^2=u^2-2as
we can find the answer
distance is 100
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