Question

a scooter moving at a speed of 10m/s is stopped by applying brakes which produces uniform acceleration of 2 meter per second square. how much distance will be covered by the scooter before its stop
give correct answer​

Answer 1

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Answer 2

Given:

• Initial velocity(u) = 10m/s

• Final velocity(v) = 0m/s

• Acceleration(a) = 2m/s^2

To find:

• The distance(s) covered by the scooter before it stops.

Solution:

We know that,

$\sf\tt\bf{ {v}^{2} - {u}^{2} = 2as}{\tiny \: (Third \: equation \: of \: motion)}$

• Putting values in the formula

$\sf\rightsquigarrow \: \: { {0}^{2} = {10}^{2} + 2 \times ( - 2) \times\:s}$

$\sf\rightsquigarrow \: \: {0 = {10}^{2} + 2( - 2)s}$

$\sf\rightsquigarrow \: \: {0 = 100 + 2( - 2)s}$

$\sf\rightsquigarrow \: \: {0 = 100 - 4s}$

$\sf\rightsquigarrow \: \: {100 - 4s = 0}$

$\sf\rightsquigarrow \: \: { - 4s = - 100}$

$\sf\rightsquigarrow \: \: {s = \cancel\frac{ - 100}{ - 4} }$

$\sf\rightsquigarrow \: \: {s = 25}$

$\sf\bf\therefore{The \: distance \: covered \: by \: the \:}$

$\sf\bf{scooter \: before \: it \: stops \: is \: 25m}$