Question

A SCOOTER MOVING AT A SPEED OF 10M/S IS STOPPED BY BRAKES WHICH PRODUCE A UNIFORM ACCELERATION - 0.5 M/S . HOW MUCH DISTANCE COVERED BY SCOOTER BEFORE IT STOPS

Answer 1

Explanation:

A scooter moving at a speed of 10 m/s is stopped by applying brakes which produce a uniform acceleration of, -0.5 m/s2. How much distance will be covered by the scooter before it stops ? Thus, the distance covered is 100 metres

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Answer 2

QuEsTiOn :-

A scooter moving at a speed of 10 m/s is stopped by applying brakes which produce a uniform acceleration of 0.5 m/s, how much distance covered by scooter before it stops ?

AnSweR :-

• The distance covered by the scooter is 100 metres

Given :-

• Initial speed ( u ) = 10 m/s

• Final speed ( v ) = 0 m/s

• Acceleration ( a ) = -5 m/s²

To be calculated :-

Calculate the distance covered by the scooter before it stops.

Solution :-

According to the third equation of motion,

v² = u² + 2as

Where ,

• Initial speed = ( u )

• Final speed = ( v )

• Acceleration = ( a )

• Distance covered = ( s)

Now ,

➤ Putting the values in the third equation of motion

we get :

⇒ ( 0 )² = ( 10 )² + 2 × ( -0.5 ) × s

⇒ 0 = 100 - s

⇒ s = 100

⇒ s = 100/10

⇒ s = 100 m

Thus,

The distance covered by the scooter is 100 metres.

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➤ Extra shots :-

v = u + at ( first equation of motion )

s = ut + ½ at² ( second equation of motion )

v² = u² + 2as ( third equation of motion )

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