Question

A scooter moving at a speed of 10m/s² is stopped by applying brakes which produce acceleration of -0.5m/s². How much distance will be covered by the scooter?​ ​

Answer 1

Given :-

• A scooter moving at a speed of 10m/s² is stopped by applying brakes Which produce acceleration of -0.5m/s².

To find :-

• How much dictance will be covered by the scooter?

Solution :-

• Initial velocity = 10m/s

• Acceleration = 0.5 m/s²

• Final velocity = 0

According to third equation of motion

→ v² = u² + 2as

Where " v " is final velocity, " u " is initial velocity, " a " is acceleration and " s " is distance.

→ (0)² = (10)² + 2 × (-0.5) × s

→ 0 = 100 - 1 × s

→ 0 = 100 - s

→ s = 100 m

Hence,

• Distance will be covered by the scooter is 100m

More to know :-

• s = ut + ½ at² (second equation of motion)
• v = u + at (first equation of motion)
• Acceleration is the rate of change in velocity.
• Acceleration is negative is know as retardation

Answer 2

Given :-

• A scooter moving at a speed of 10m/s² is stopped by applying brakes Which produce acceleration of -0.5m/s².

To find :-

• How much dictance will be covered by the scooter?

Solution :-

• Initial velocity

• Acceleration

• Final velocity =