Question

A scooter moving at a speed of 50m/s is stopped by applying brakes which produce a uniform accerleration of -0.5m/s².How much distance will be covered by the scooter
before it stops.

PLEASE ANSWER THS

Answer 1

apply newton's eq. of motion

v^2=u^2+2as

where v = final velocity which will be zero becoz it wants to stop the scooter

u = initial velocity

=50 m/s (given)

a= acceleration

= -0.5 m/s^2 (given)

s = distance = ?

u have ur ans 2500 m

Answer 2

Answer:

Distance = 2500 m

Explanation:

Initial velocity = 50 m/s, Final velocity = 0 m/s, Acceleration = -0.5 m/s^2

Distance = ?

v^2 - u^2 = 2as (Third Equation Of Motion)

0^2 - 50^2 = 2(-0.5)(s)

0 - 2500 = -1s

s = 2500 m