a scooter moving with a velocity of 18km/h is brought to rest in 5sec by applying breaks. What is the retardation produced?
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Its an easy one
according to equation of motion
v=u-at
at=u-v
a=(18-0)÷5
r=18÷5
hence retardation =3.6ms^(-2)
according to equation of motion
v=u-at
at=u-v
a=(18-0)÷5
r=18÷5
hence retardation =3.6ms^(-2)
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