a scooter of mass 120 kg is moving with a uniform velocity of 108km Hr .The force required to stop the vehicle in 10 seconds is ?
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MASS = 120 KG
INITIAL VELOCITY (U)= 108 KM/HR = 30 M/S
FINAL VELOCITY (V)= 0 M/S
TIME= 10 SECONDS
FORCE=?
FORCE = MASS*ACCLEREATION
FORCE= MASS*V-U/T
FORCE=120*0-30/10
FORCE=120*-30/10
FORCE=120*-3
FORCE= -40 N
THAT IS FORCE IS 40 N OPPOSITE THE DIRECTION OF SCOOTER
INITIAL VELOCITY (U)= 108 KM/HR = 30 M/S
FINAL VELOCITY (V)= 0 M/S
TIME= 10 SECONDS
FORCE=?
FORCE = MASS*ACCLEREATION
FORCE= MASS*V-U/T
FORCE=120*0-30/10
FORCE=120*-30/10
FORCE=120*-3
FORCE= -40 N
THAT IS FORCE IS 40 N OPPOSITE THE DIRECTION OF SCOOTER
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