A scooter of mass 120 kg is moving with a uniform velocity of 108 km/lu. The magnitude of force required to stop the vehicle in 10 sec is (40 k) Newton, then find the value of k.
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Answer:
360N
Explanation:
mass of the object =120kg
initial velocity of the object = 108km/hr (30m/s)
final velocity of the object = 0m/s
given time =10sec.
Therefore force,
force = change in momentum/time taken
F= (mv-mu)/t
F= (120*0-120*30)/10
F= (0-3600)/10
F=-3600/10
F= -360N
therefore the answer in magnitude is 360N
Hope this will help you
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