Math, asked by sannyashi9013, 2 days ago

A scooter of mass 120 kg is moving with a uniform velocity of 54 km/h. The force required to stop the scooter in 10 s will be

Answers

Answered by Anonymous
2

Step-by-step explanation:

Force = change in momentum / change in time

mass = 120 kg

velocity = 54 km/hr

= 54 * 1000/3600

= 15 m/s

Initial momentum = m * v

= 120 * 15

= 1800 Kg. m/s

final momentum = 0

Force = (1800 Kg. m/s) / (10 s)

= 180 N

Answered by ipman2882004
1

Answer:

180N

Step-by-step explanation:

Initial velocity of scooter = 54kph = 54*1000/3600= 15m/s= vi

Final velocity =0m/s=vi

Time= 10s=t

Mass=120kg

Deceleration = - a=vf - vi/t = 0-15(m/s)/10sec = - 1.5m/s/s

-a= - 1.5m/s/s = a=1.5m/s/s

Force = F= ma = kgm/s/s = N

= 120kg x 1.5m/s/s = 180kgm/s/s

Force Required To Stop The Scooter is 180N

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