A scooter of mass 120 kg is moving with uniform velocity of 108 km/hr.The force required to stop the vehicle in 10 sec is ..
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Given,
Mass of the scooter = 120 kg
Velocity, u = 108 km/h = 30 m/s and v = 0 m/s
Time = 10 seconds
Now,
V = u + at
a = (v - u) / t
a = (0 - 30) / 10
a = -3 m/s²
Force = Mass × Acceleration
F = ma
F = 120 × (-3)
F = -360N
Here negative sign means force is on opposite direction with respect to the motion of the scooter.
Mass of the scooter = 120 kg
Velocity, u = 108 km/h = 30 m/s and v = 0 m/s
Time = 10 seconds
Now,
V = u + at
a = (v - u) / t
a = (0 - 30) / 10
a = -3 m/s²
Force = Mass × Acceleration
F = ma
F = 120 × (-3)
F = -360N
Here negative sign means force is on opposite direction with respect to the motion of the scooter.
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