A scooter starts from rest,moves in a straight line with constant acceleration and covers a distance of 64m in 4 seconds. Calculate it's acceleration and final velocity
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to find out the acceleration of the scooter we use second equation of motion
s= ut + 1/2at²
64 = 0 × 4 +1/2a * 4²
64 = 0 +1/2a * 16
64 *2/16 = a
8m/s² = a
now to calculate the the final velocity we use first equation of motion
v = u + at
v = 0 + 8 × 4
= 32 m/s
The time taken by the scooter to travel of the distance i. e; 32 m using
s= ut + 1/2at²
32 = 0 *4 + 1/2 * 8 * t²
32 = 4 * t ²
32/ 4 = t²
8= t²
√8 = t
2√2 = t
s= ut + 1/2at²
64 = 0 × 4 +1/2a * 4²
64 = 0 +1/2a * 16
64 *2/16 = a
8m/s² = a
now to calculate the the final velocity we use first equation of motion
v = u + at
v = 0 + 8 × 4
= 32 m/s
The time taken by the scooter to travel of the distance i. e; 32 m using
s= ut + 1/2at²
32 = 0 *4 + 1/2 * 8 * t²
32 = 4 * t ²
32/ 4 = t²
8= t²
√8 = t
2√2 = t
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