A scooter starts from rest ,moves in a straight line with a constant acceleration and covers a distance of 64m in 4 seconds a . calculate acceleration B final velocity
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accelerating a =(v-u)/t= v/t=64/4= 16m per sec square
final velocity will be v=at = 16×4 = 64 m per sec
final velocity will be v=at = 16×4 = 64 m per sec
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a scooter starts from rest.....therefore its initial
velocity is = 0 m/s...
distance covered.= 64 metres
time taken = 4 seconds
to find = acceleration ??
we know that .... s = ut + 1/2×t×t
from then given information
.... 64 = 0 × 4 + 1/2 × a × 4 × 4
.... 64 = 8a
..... a = 64/8
.... a = 8 m/s2.
here .....m/s2 is metre per second square
hope this helps...!!!
velocity is = 0 m/s...
distance covered.= 64 metres
time taken = 4 seconds
to find = acceleration ??
we know that .... s = ut + 1/2×t×t
from then given information
.... 64 = 0 × 4 + 1/2 × a × 4 × 4
.... 64 = 8a
..... a = 64/8
.... a = 8 m/s2.
here .....m/s2 is metre per second square
hope this helps...!!!
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