A scooter travel from station a to station b at a uniform speed of 60 kilometre per hour. it return immediately after reaching station b back to stationa and travel at a uniform speed of 70 km per hour. find the average speed of the scooters
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Answered by
44
let distance between the stations be x kms
time taken to go from a to b = x/60
time taken to come back =x/70
total time =x/60 + x/70 = 13x/420
average speed =total distance / total time
avg speed = 2x/(13x/420)
=(2×420)/13
=64.61 km/h
time taken to go from a to b = x/60
time taken to come back =x/70
total time =x/60 + x/70 = 13x/420
average speed =total distance / total time
avg speed = 2x/(13x/420)
=(2×420)/13
=64.61 km/h
Answered by
2
Answer:
64.6
Step-by-step explanation:
here the speed between station A to station B is given 60 km/hr and speed from returning station B to station A is given 70 km/hr.
So here we can assume distance x km.
by taking this , the total distance covered by a scooter is equals to 2 x
as we have distance = X km
we can find T¹ take in to cover the distance between station A to station B.
by putting the formula of time = distance/speed
= x/60 seconds
now we can find T²= x/70
total time=T¹+T²
=x/60+x/70
= 13x/420
Now let's find the average speed...
Average speed= Total distance/total time taken
2x ÷ (13x/420)
2x × 420/13x
=64.6 km/hr
the final answer is 64.6 km/hr
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