Question

A scooter travelling at 10 m/s speed up to 20 m/s in 4 sec. Find the acceleration of scooter.​

Answer 1

Answer:

$a=2.5m/s^2$

Explanation:

Given,

Initial Velocity(u) = 10m/s

Final Velocity(v) = 20m/s

time(t) = 4s

To Find :-

Acceleration(a) of the scooter.

Formula Required :-

$a=\dfrac{v-u}{t}$

Solution :-

$a=\dfrac{20-10}{4}$

$=\dfrac{10}{4}$

$=\dfrac{5}{2}$

$a=2.5m/s^2$

Know More :-

Useful Kinematic Formulas :-

$1) v = u+at$

$2)s=ut+\dfrac{1}{2}at^2$

$3)s=vt-\dfrac{1}{2}at^2$

$4)v=\sqrt{2gh}$

$5)v^2-u^2=2as$

Answer 2

Given:-

• Initial Speed/Velocity (u) = 10 m/s

• Final Speed/Velocity (v) = 20 m/s

• Time taken = 4 sec

To Find:-

• Acceleration of scooter.

Law used:-

• ${\boxed{First\:Law \:of \:Motion: v = u + at}}$

Solution:-

Putting the values in it,

$:\implies\:v=u+at$

$:\implies\:20=10+a\times 4$

$:\implies\:20-10=a\times 4$

$:\implies\:a=\dfrac{10}{4}$

$:\implies\:a=\dfrac{5}{2}$

${\boxed{:\implies\:a=2.5ms^{-2}}}$

Hence, The acceleration of scooter is 2.5m/s².

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More to know:-

• $s=ut+\dfrac{1}{2}at^2$

• $v^2-u^2=2as$

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