Question

A scooter travelling with speed of 36 km/hr comes to rest in 5 sec.What is its deceleration

Answer 1

a=v-u/t
=0-36/5
-36/5
=-7.2m/s^2

Answer 2

initial velocity (u)=36÷5/8
=22.5m/s
time= 5sec
final velocity (v)= 0
deceleration = v-u/t
= 0-22.5/5
=-4.5m/s^2