Question

A scooter was bought at 42,000. Its value depreciated at the rate of 8% per annum. Find its value after one year.

Pls don't answer unnecessarily.​

Answer 1

Answer:

Here, Principal (P) = Rs. 42,000, Rate of Interest (R) = 8%, Time (n) = 1 years.

Amount (A) = P\left(1-\frac{R}{100}\right)^n

= 42000\left(1-\frac{8}{100}\right)^1

= 42000\left(1+\frac{2}{25}\right)^1

= 42000\left(\frac{27}{25}\right)^1

= 42000\times\frac{27}{25}

= Rs. 38,640

Hence, the value of scooter after one year is Rs. 38,640.

Answer 2

Answer:

Rs 38,640

Explanation:

Principal Rate = Rs 42,000

Interest= 8℅

Time = 1 year

8/100*42,000 = 3360

42,000 - 3360 = 38640

Therefore, the value after one year is Rs 38640