Question

A scooter was bought at ₹ 42,000. Its value depriciated at the rate of 8% per annum. find its value after one year.

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Answer 1

$\huge {\underline{\mathbb{SOLUTION:-}}}$

Given:

• P = ₹ 42,000
• R = 8%
• T = 1 year

Need to find:

• Value of the scooter after one year

Answer:

• The value of the scooter after one year is ₹ 3,8640.

Step by step explanation:

Interest = P×R×T/100

=> 42000×8×1/100

=> ₹ 3360

As we know that,

Amount = Principal - Interest

=> 42000 - 3360

=> 38640

Hence, value of the scooter at the end of one year is ₹ 38,640.

SHORTCUT METHOD:-

As we know that,

$\large {Amount = P(1 - \frac{R}{100} ) ^{n} } \\ \large \implies{42000(1 - \frac{8}{100} )} \\ \large \implies{42000 \times \frac{92}{100}} \\ \large \implies{ \bold{ 38640}}$

Answer 2

$\huge\underline\mathrm{SOLUTION:-}$

AnswEr:

• The value of scooter after one year = Rs. 38,640.

Given:

• A scooter was bought at ₹ 42,000.
• Its value depriciated at the rate of 8% per annum.

Need To Find:

• It's value after one year = ?

ExPlanation:

Here, 8% P.A is depreciated.

• Depreciated means value is decreased.

So, We put a minus sign in Rate.

ThereFore,

Rate = -8%

• Since, the rate is compounded.

Formula Used Here:

• A = P(1 + R/100)^3

Here,

• P = ₹ 42,000
• R = -8% P.A
• N = 1 years

Putting the values in formula:

A = 42,000 (1 + -8/100)¹

= 42000 (1 - 8/100)

= 42000 (100 - 8/100)

= 42000 (92/100)

= 420 × 92

= $\sf {\boxed{\sf\red{38,640}}}$

• Hence, the value of scooter after one year is Rs. 38,640.

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Additional Information:

Here,

• P is used for Principal.
• R is used for Rate of interest.
• N is used for Time.
• A is used for Amount.

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