Question

A scooter was bought at 42000.Its value depreciated at the rate of 8% per Annum.Find it's value after one year.

Answer 1

Answer:

Is the question from NCERT

Step-by-step explanation

First we'll find out 8% of 42000= 3360

Now we'll subtract it from 42000

= 38640

Answer 2

Hey mate here is your answer,

P= Rs42000
Depreciation rate= 8% p.a.
time= 1 year OR n=1
Using A=P( 1 + r/100 )n
we have,
A=Rs 42000( 1 - 8/100 )1
A= Rs 42000 × 92/100
A= Rs 420×92
A= Rs 38640
Thus,the value of the scooter after 1 year will be Rs 38640.
Hope it helps you