Question

A scooter was bought at ₹42000 . Its value depreciated at the rate of 8 % p.a. Find its value after 2 years.

Answer 1

P= 42000

R=8 %

T=2

$a = p \times {(1 - \frac{ r}{100} )}^{n} \\ a = 42000 \times { (1 - \frac{8}{100}) }^{2} \\ a = 42000 \times \frac{529}{25 \times 25} \\ a = 35548.8$

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